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#1 |
N00t me
Datum registracije: Apr 2009
Lokacija: Mostar
Postovi: 2
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![]() imam problem, i to malo veći znaci kroz nekakve procedure naći aritmetičku sredinu... Fino odradim max član, pa min član. Max spremim u bl (8bitni su brojevi), a min u bh... Problem nastaje kada zelim ispisati (izračunati) aritmetičku sredinu (min i max clana), te mi uporno ispisuje 6 (kao brojeve unesem 1, 2, 3, 4, 5)... Jel tko zna bar u čemu je problem... Nemojte samo reć ![]() ![]() ![]() ![]()
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#2 |
Guest
Datum registracije: Jun 2008
Lokacija: Splity
Postovi: 3,003
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Oglas
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#3 | |
E Pluribus UNIX
Datum registracije: Oct 2002
Lokacija: M82
Postovi: 6,748
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Citiraj:
Pogledaj ovo: Code:
$ cat arithmetic.c #include <stdio.h> int ax, dl, ah, al, ah_b, al_b; int main() { __asm__( "mov $0, %ax \n" "mov $1, %dl \n" "add %dl,%al \n" "mov $2,%dl \n" "add %dl,%al \n" "mov $3,%dl \n" "add %dl,%al \n" "mov $4,%dl \n" "add %dl,%al \n" "mov $5,%dl \n" "add %dl,%al \n" "mov %al, al_b \n" "mov %ah, ah_b \n" "mov $9,%dl \n" "div %dl \n" "mov %dl, dl \n" "mov %al, al \n" "mov %ah, ah \n" ); printf("Before division:\tAL %d\tAH %d\nDivided by:\t\tDL %d\nAfter division:\t\tAL %d\tAH %d\n", al_b, ah_b, dl, al, ah); return 0; } $ gcc -O2 -fomit-frame-pointer -W -Wall -g arithmetic.c -o arithmetic.asm $ ./arithmetic.asm Before division: AL 15 AH 0 Divided by: DL 9 After division: AL 1 AH 6 Code:
Before division: AL 15 AH 0 Divided by: DL 5 After division: AL 3 AH 0 Dakle, treba nam tvoj kod da vidimo gdje je zapelo...
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#4 |
N00t me
Datum registracije: Apr 2009
Lokacija: Mostar
Postovi: 2
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![]() ![]() ![]() naso sam problem
__________________
You got to ask yourself one question: "Do i feel lucky? Well do ya punk!" |
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